Bio 6D - Compare genetic variations in plants and animal (HOLT Ch. 8)
Multiple Choice
Identify the
letter of the choice that best completes the statement or answers the question.
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1.
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The
difference between Mendel's experiments in the area of heredity and those done by earlier researchers
was that a. | earlier
researchers did not have microscopes. | b. | earlier researchers used detailed and numerical
procedures. | c. | Mendel expressed the results of his experiments in terms of
numbers. | d. | Mendel used pea plants with both purple and white
flowers. | | |
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2.
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The
scientific study of heredity is called a. | meiosis | c. | genetics | b. | crossing-over | d. | pollination | | | | |
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3.
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The
“father” of genetics was a. | A. Knight | c. | Gregor Mendel. | b. | Hans
Krebs. | d. | None of the
above | | | | |
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4.
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Mendel obtained his P generation by allowing the plants to a. | self-pollinate. | c. | assort
independently. | b. | cross-pollinate. | d. | segregate. | | | | |
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5.
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Step
1 of Mendel's garden pea experiment, allowing each variety of garden pea to self-pollinate for
several generations, produced the a. | F1 generation. | c. | P generation. | b. | F2
generation. | d. | P1
generation. | | | | |
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6.
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F2 : F1 :: a. | P : F1 | c. | F1 : P. | b. | F1 :
F2 | d. | dominant trait :
recessive trait | | | | |
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7.
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Garden peas a. | are difficult to grow. | b. | mature
quickly. | c. | produce few offspring. | d. | are not good
subjects for studying heredity. | | |
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8.
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If an
individual possesses two recessive alleles for the same trait, the individual is said to
be a. | homozygous for
the trait. | c. | heterozygous for
the trait. | b. | haploid for the trait. | d. | mutated. | | | | |
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9.
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Tallness (T) is dominant to shortness (t) in pea plants. Which of the
following represents a genotype of a pea plant that is heterozygous for tallness?
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10.
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A 3:1
ratio of tall to short pea plants appearing in the F2 generation lends support to the law
of a. | recessiveness. | c. | mutation. | b. | segregation. | d. | crossing-over. | | | | |
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In humans, having freckles (F) is dominant to not having freckles (f).
The inheritance of these traits can be studied using a Punnett square similar to the one shown
below.
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11.
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Refer
to the illustration above. The child represented in box 1 in the Punnett square
would a. | be homozygous
for freckles. | c. | be heterozygous
for freckles. | b. | have an extra freckles
chromosome. | d. | not have
freckles. | | | | |
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12.
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Refer
to the illustration above. The parents shown in the Punnett square could have children with a
phenotype ratio of a. | 1:2:1. | c. | 3:1. | b. | 4:0. | d. | 2:2. | | | | |
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13.
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Refer
to the illustration above. Which box in the Punnett square represents a child who does not
have freckles? a. | box
1 | c. | box
3 | b. | box
2 | d. | box
4 | | | | |
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In rabbits, black fur (B) is dominant to brown fur (b).
Consider the following cross between two rabbits.
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14.
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Refer
to the illustration above. The device shown, which is used to determine the probable outcome of
genetic crosses, is called a a. | Mendelian box. | c. | genetic graph. | b. | Punnett
square. | d. | phenotypic
paradox. | | | | |
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15.
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Refer
to the illustration above. The phenotype of the offspring indicated by box 3 would
be a. | brown. | c. | a mixture of
brown and black. | b. | black. | d. | None of the above | | | | |
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16.
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What
is the expected genotypic ratio resulting from a heterozygous ´ heterozygous
monohybrid cross?
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17.
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What
is the expected phenotypic ratio resulting from a homozygous dominant ´ heterozygous
monohybrid cross?
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18.
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The
unknown genotype of an individual with a dominant phenotype can be determined using a. | a
ratio. | c. | probability | b. | a dihybrid cross. | d. | a test cross. | | | | |
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19.
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A
trait that occurs in 450 individuals out of a total of 1,800 individuals occurs with a probability
of a. | 0.04 | c. | 0.50. | b. | 0.25. | d. | 0.75. | | | | |
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20.
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If a
characteristic is sex-linked, it a. | occurs most commonly in males. | c. | can never occur in females. | b. | occurs only in
females. | d. | is always
fatal. | | | | |
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21.
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In
humans, the risks of passing on a genetic disorder to offspring can be assessed by a. | analysis of a
pedigree. | c. | prenatal
testing. | b. | genetic counseling. | d. | All of the above | | | | |
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22.
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How
many different phenotypes can be produced by a pair of codominant alleles?
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23.
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What
would be the blood type of a person who inherited an A allele from one parent and an O
allele from the other? a. | type A | c. | type AB | b. | type
B | d. | type
O | | | | |
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24.
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Which
of the following describes hemophilia? a. | multiple-allele trait | c. | sex-linked trait | b. | dominant
trait | d. | codominant
trait | | | | |
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25.
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Genetic counseling is a process that a. | helps identify
parents at risk for having children with genetic defects. | b. | assists parents
in deciding whether or not to have children. | c. | uses a family
pedigree. | d. | All of the above | | |
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